What is the integral of 7e^{-x} ?

The integral of 7e^{-x} is -7e^{-x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 7e^{-x}

\int 7 e^{- x} d x

- 7 e^{- x} + C

Solution steps

\int 7 e^{- x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int e^{- x} d x

Apply u-substitution

: \int - e^{u} d u

= 7 \cdot \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 (- \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 7 (- e^{u})

Substitute back

u = - x

= 7 (- e^{- x})

Simplify

= - 7 e^{- x}

Add a constant to the solution

= - 7 e^{- x} + C

e^{x}, e^{- x}, - 2, 1

x \to + (- 3) - lim (4 x^{2} - 6 x + 3)

\frac{\partial}{\partial y} (x^{3} e^{x y} + 2 y)

\int 3 t e^{3 t} d t

x \to - 1 lim (\frac{2 x + 2}{x + 1})