What is the derivative of 5xe^xcsc(x) ?

The derivative of 5xe^xcsc(x) is 5(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

What is the first derivative of 5xe^xcsc(x) ?

The first derivative of 5xe^xcsc(x) is 5(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

5 x e^{x} csc (x)

5 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

Solution steps

\frac{d}{d x} (5 x e^{x} csc (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (x e^{x} csc (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x} csc (x)

= 5 (\frac{d x}{d x} e^{x} csc (x) + \frac{d}{d x} (e^{x} csc (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x} csc (x)) = e^{x} csc (x) - e^{x} cot (x) csc (x)

= 5 (1 \cdot e^{x} csc (x) + (e^{x} csc (x) - e^{x} cot (x) csc (x)) x)

Simplify

= 5 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

\int_{0}^{\infty} t \cdot e^{- s t} d t

\frac{d y}{d x}, y = x^{2} + 2

\int_{7}^{8} \frac{x}{x ^{2} + 4 x + 13} d x

\frac{1}{s} e^{- 2 s}

f (x) = 3 ln (x) + 4 e^{x} - 5 x^{2}

What is the derivative of 5xe^xcsc(x) ?
The derivative of 5xe^xcsc(x) is 5(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))
What is the first derivative of 5xe^xcsc(x) ?
The first derivative of 5xe^xcsc(x) is 5(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))