What is the limit as x approaches 0 of 2sqrt(x+1)-1 ?

The limit as x approaches 0 of 2sqrt(x+1)-1 is 1

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limit as x approaches 0 of 2sqrt(x+1)-1

x \to 0 lim (2 x + 1 - 1)

1

Solution steps

x \to 0 lim (2 x + 1 - 1)

Plug in the value

x = 0

= 2 0 + 1 - 1

Simplify

= 1

\frac{d}{d x} ((ln (3 x))^{5})

2 x^{2} - 7 x + k

\int (6 x) d x

y = - 3 x^{3} - 3 x^{2} - x + 3, (- 1, 4)

y^{^{''}} + 2 y^{^{'}} + 2 = cos (t), y (0) = 0, y^{^{'}} (0) = 0

What is the limit as x approaches 0 of 2sqrt(x+1)-1 ?
The limit as x approaches 0 of 2sqrt(x+1)-1 is 1