What is (\partial)/(\partial x)(x^2+3yz+4xy) ?

The answer to (\partial)/(\partial x)(x^2+3yz+4xy) is 2x+4y

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(\partial)/(\partial x)(x^2+3yz+4xy)

\frac{\partial}{\partial x} (x^{2} + 3 yz + 4 x y)

2 x + 4 y

Solution steps

\frac{\partial}{\partial x} (x^{2} + 3 yz + 4 x y)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (3 yz) + \frac{\partial}{\partial x} (4 x y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 yz) = 0

\frac{\partial}{\partial x} (4 x y) = 4 y

= 2 x + 0 + 4 y

Simplify

= 2 x + 4 y

y^{^{'}} = (x y^{^{'}} + y) y^{1} 985

\frac{d}{d x} (\frac{2 x}{x ^{3}})

\frac{\partial}{\partial y} (ln (2 x^{3} + 3 y^{2}))

\frac{7 x}{x - 3}

n = 0 \sum \infty 7 (0.1)^{n}

What is (\partial)/(\partial x)(x^2+3yz+4xy) ?
The answer to (\partial)/(\partial x)(x^2+3yz+4xy) is 2x+4y