What is the integral from 0 to 2 of (x^2)^2 ?

The integral from 0 to 2 of (x^2)^2 is 32/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (x^2)^2

\int_{0}^{2} (x^{2})^{2} d x

\frac{32}{5}

Decimal

6.4

Solution steps

\int_{0}^{2} (x^{2})^{2} d x

Simplify

(x^{2})^{2} : x^{4}

= \int_{0}^{2} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{0}^{2}

= [\frac{x ^{5}}{5}]_{0}^{2}

Compute the boundaries:

\frac{32}{5}

= \frac{32}{5}

x \to 0 lim (\frac{1}{1 - e ^{x}} - \frac{1}{x})

w (x) = (x^{2} (2^{x}))^{3}

\int e^{x^{2}} x d x

\int 120 x (2 x + 1)^{4} d x

\frac{d}{d x} ((\frac{3 x ^{2} - 2}{2 x + 3})^{- 2})

What is the integral from 0 to 2 of (x^2)^2 ?
The integral from 0 to 2 of (x^2)^2 is 32/5