What is the derivative of 4x^2-3x+1 ?

The derivative of 4x^2-3x+1 is 8x-3

What is the first derivative of 4x^2-3x+1 ?

The first derivative of 4x^2-3x+1 is 8x-3

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\frac{d}{d x} (4 x^{2} - 3 x + 1)

8 x - 3

Solution steps

\frac{d}{d x} (4 x^{2} - 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 8 x - 3 + 0

Simplify

= 8 x - 3

\frac{\partial}{\partial x} (2 \frac{y}{x})

x \to 0 lim (e^{4 x})

\frac{d x}{d t} = 6.4286 - 0.10714 x

y = 5^{x^{3}}

\frac{8 x}{x ^{2} - 1}

What is the derivative of 4x^2-3x+1 ?
The derivative of 4x^2-3x+1 is 8x-3
What is the first derivative of 4x^2-3x+1 ?
The first derivative of 4x^2-3x+1 is 8x-3