What is the solution for 3x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 ?

The solution for 3x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 is y=(sqrt(3\sqrt{x^2+1)+141})/2

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3x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6

3 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 6

y = \frac{3 x ^{2} + 1 + 141}{2}

Solution steps

3 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{3 x ^{2} + 1 + 141}{2}

y = \frac{3 x ^{2} + 1 + 141}{2}

\int \frac{x - 3}{x ^{2} + 4 x + 8} d x

\int_{0}^{1} e^{3 x} d x

y = 11 x^{5} - 2 x^{3} + 6 x - 8

4 y^{^{''}} + 2 y^{^{'}} + 7 y = 0

2^{x}, 4^{x}, \frac{1}{x}

What is the solution for 3x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 ?
The solution for 3x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 is y=(sqrt(3\sqrt{x^2+1)+141})/2