What is the integral of-\sqrt[4]{x} ?

The integral of-\sqrt[4]{x} is -4/5 x^{5/4}+C

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integral of-\sqrt[4]{x}

\int - 4 x d x

- \frac{4}{5} x^{\frac{5}{4}} + C

Solution steps

\int - 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int 4 x d x

Apply the Power Rule

: \frac{4}{5} x^{\frac{5}{4}}

= - \frac{4}{5} x^{\frac{5}{4}}

Add a constant to the solution

= - \frac{4}{5} x^{\frac{5}{4}} + C

\frac{d y}{d x} = \frac{y ( - 2 x + 4 )}{( x ^{2} + 1 ) ( x - 1 ) ^{2}}

3 arccos (\frac{x}{2})

x \to 0 lim (\frac{3 ^{x} - 1 1 ^{x}}{x})

x \to 3 + lim (sec (\frac{π x}{6}))

\int \frac{( x - 2 ) ( x + 3 )}{x ^{2}} d x

What is the integral of-\sqrt[4]{x} ?
The integral of-\sqrt[4]{x} is -4/5 x^{5/4}+C