What is the tangent of f(x)= 2/(x-1),(3,1) ?

The tangent of f(x)= 2/(x-1),(3,1) is y=-1/2 x+5/2

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tangent of f(x)= 2/(x-1),(3,1)

tangent of

f (x) = \frac{2}{x - 1}, (3, 1)

y = - \frac{1}{2} x + \frac{5}{2}

Solution steps

Find the slope of

f (x) = \frac{2}{x - 1} : \frac{df ( x )}{d x} = - \frac{2}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(3, 1) : y = - \frac{1}{2} x + \frac{5}{2}

y = - \frac{1}{2} x + \frac{5}{2}

\int x e^{- 3 x} d x

\frac{d}{d y} (\frac{1}{3} y (y - 3))

\frac{d}{d x} (x^{l n (x^{2} + 1)})

\frac{d ^{2}}{d x ^{2}} (e^{s i n (x)})

\frac{d}{d x} ((sin (y)) x^{2})

What is the tangent of f(x)= 2/(x-1),(3,1) ?
The tangent of f(x)= 2/(x-1),(3,1) is y=-1/2 x+5/2