What is (\partial)/(\partial y)(xyz^2) ?

The answer to (\partial)/(\partial y)(xyz^2) is xz^2

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(\partial)/(\partial y)(xyz^2)

\frac{\partial}{\partial y} (x y z^{2})

x z^{2}

Solution steps

\frac{\partial}{\partial y} (x y z^{2})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x z^{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= x z^{2} \cdot 1

Simplify

= x z^{2}

x \to \infty lim (- 0. 5^{x})

\int \frac{4 x ^{4} + 3}{4 x ^{5} + 15 x + 2} d x

ln (sin (4 x))

\frac{\partial}{\partial x} (x y z^{2})

\frac{d}{d y} (x y + y x^{2} + y^{2})

What is (\partial)/(\partial y)(xyz^2) ?
The answer to (\partial)/(\partial y)(xyz^2) is xz^2