What is the solution for (dx}{dy}=-\frac{4y)/x ?

The solution for (dx}{dy}=-\frac{4y)/x is x=sqrt(-4y^2+c_{1)},x=-sqrt(-4y^2+c_{1)}

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(dx}{dy}=-\frac{4y)/x

\frac{d x}{d y} = - \frac{4 y}{x}

x = - 4 y^{2} + c_{1}, x = - - 4 y^{2} + c_{1}

Solution steps

\frac{d x}{d y} = - \frac{4 y}{x}

Solve separable ODE:

x = - 4 y^{2} + c_{1}, x = - - 4 y^{2} + c_{1}

x = - 4 y^{2} + c_{1}, x = - - 4 y^{2} + c_{1}

y ln (x) y^{^{'}} = (\frac{y + 1}{x})^{2}

\int 3 cos^{3} (5 x) d x

\frac{e ^{2 x}}{x}

f (x) = \frac{x ^{2} - 2}{2 x + 1}

\int \frac{e ^{2 t}}{1 - e ^{2 t}} d t

What is the solution for (dx}{dy}=-\frac{4y)/x ?
The solution for (dx}{dy}=-\frac{4y)/x is x=sqrt(-4y^2+c_{1)},x=-sqrt(-4y^2+c_{1)}