What is the tangent of y= 3/(sqrt(x)),(1,3) ?

The tangent of y= 3/(sqrt(x)),(1,3) is y=-3/2 x+9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y= 3/(sqrt(x)),(1,3)

tangent of

y = \frac{3}{x}, (1, 3)

y = - \frac{3}{2} x + \frac{9}{2}

Solution steps

Find the slope of

y = \frac{3}{x} : \frac{d y}{d x} = - \frac{3}{2 x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(1, 3) : y = - \frac{3}{2} x + \frac{9}{2}

y = - \frac{3}{2} x + \frac{9}{2}

\int t^{5} - 5 t d t

y^{^{'''}} - y = 0

\int \frac{x}{2 + 2 x ^{2}} d x

\frac{1 + x}{4 - x}

\int \frac{3 x + 1}{( x - 4 ) ( x - 2 )} d x

What is the tangent of y= 3/(sqrt(x)),(1,3) ?
The tangent of y= 3/(sqrt(x)),(1,3) is y=-3/2 x+9/2