What is the integral of e^{cos(27t)}sin(27t) ?

The integral of e^{cos(27t)}sin(27t) is -1/27 e^{cos(27t)}+C

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integral of e^{cos(27t)}sin(27t)

\int e^{c o s (27 t)} sin (27 t) d t

- \frac{1}{27} e^{c o s (27 t)} + C

Solution steps

\int e^{c o s (27 t)} sin (27 t) d t

Apply u-substitution

: \int e^{c o s (u)} sin (u) \frac{1}{27} d u

= \int e^{c o s (u)} sin (u) \frac{1}{27} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{27} \cdot \int e^{c o s (u)} sin (u) d u

Apply u-substitution

: \int - e^{v} d v

= \frac{1}{27} \cdot \int - e^{v} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{27} (- \int e^{v} d v)

Use the common integral:

\int e^{v} d v = e^{v}

= \frac{1}{27} (- e^{v})

Substitute back

= \frac{1}{27} (- e^{c o s (27 t)})

Simplify

= - \frac{1}{27} e^{c o s (27 t)}

Add a constant to the solution

= - \frac{1}{27} e^{c o s (27 t)} + C

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n = 0 \sum \infty \frac{x ^{n}}{n + 3}

\frac{d}{d y} (e^{x y^{2}})

\frac{d}{d x} (- \frac{2}{x})

3 x^{3} (1 + y^{2}) d x + x d y = 0

What is the integral of e^{cos(27t)}sin(27t) ?
The integral of e^{cos(27t)}sin(27t) is -1/27 e^{cos(27t)}+C