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Popular >

area y=1-x^2,y=x^2-1

Solution

area

y = 1 - x^{2}, y = x^{2} - 1

Solution

\frac{8}{3}

+1

Decimal

2.66666 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x

Solve

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x : \frac{8}{3}

The area is:

= \frac{8}{3}

Graph

Popular Examples

y^{''}+3y^'-12y=0

y^{^{''}} + 3 y^{^{'}} - 12 y = 0

derivative of y=(-13)/(\sqrt[3]{x)}derivative of

y = \frac{- 13}{3 x}

integral of sqrt(x)sin(x^{3/2}+1)

\int x sin (x^{\frac{3}{2}} + 1) d x

tangent of 1/(x+3)tangent of

\frac{1}{x + 3}

derivative of sqrt(x)(x^3-5x^2+1)

\frac{d}{d x} (x (x^{3} - 5 x^{2} + 1))

Frequently Asked Questions (FAQ)

What is area y=1-x^2,y=x^2-1 ?
The answer to area y=1-x^2,y=x^2-1 is 8/3