What is the derivative of f(x)=(2x+5)/(sqrt(x)) ?

The derivative of f(x)=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))

What is the first derivative of f(x)=(2x+5)/(sqrt(x)) ?

The first derivative of f(x)=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))

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derivative of

f (x) = \frac{2 x + 5}{x}

\frac{2 x - 5}{2 x x}

Solution steps

\frac{d}{d x} (\frac{2 x + 5}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x + 5 ) x - \frac{d}{d x} ( x ) ( 2 x + 5 )}{( x ) ^{2}}

\frac{d}{d x} (2 x + 5) = 2

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{2 x - \frac{1}{2 x} ( 2 x + 5 )}{( x ) ^{2}}

Simplify

\frac{2 x - \frac{1}{2 x} ( 2 x + 5 )}{( x ) ^{2}} : \frac{2 x - 5}{2 x x}

= \frac{2 x - 5}{2 x x}

\frac{d}{d x} (4 x^{\frac{3}{4}})

\int θ arcsec (9 θ) d θ

F (r) = \frac{4}{r ^{3}}

\frac{\partial}{\partial x} (x^{8} + y^{9} + z^{3} - 9 x yz)

x^{3} y^{^{'''}} + x y^{^{'}} - y = x^{2}

What is the derivative of f(x)=(2x+5)/(sqrt(x)) ?
The derivative of f(x)=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))
What is the first derivative of f(x)=(2x+5)/(sqrt(x)) ?
The first derivative of f(x)=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))