What is (\partial)/(\partial x)(sin(x)y^2) ?

The answer to (\partial)/(\partial x)(sin(x)y^2) is y^2cos(x)

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(\partial)/(\partial x)(sin(x)y^2)

\frac{\partial}{\partial x} (sin (x) y^{2})

y^{2} cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (x) y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= y^{2} cos (x)

\int \frac{1}{2 t ^{3}} d t

\frac{d}{d x} (3 x^{2} y^{3})

\frac{d}{d x} (x^{2} (2 x - 1)^{4})

\frac{d}{d x} (2^{5 x})

f (x) = - 7 - x^{2}, at x = 9

What is (\partial)/(\partial x)(sin(x)y^2) ?
The answer to (\partial)/(\partial x)(sin(x)y^2) is y^2cos(x)