What is the derivative of (3x^2+1^4) ?

The derivative of (3x^2+1^4) is 24x(3x^2+1)^3

What is the first derivative of (3x^2+1^4) ?

The first derivative of (3x^2+1^4) is 24x(3x^2+1)^3

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\frac{d}{d x} ((3 x^{2} + 1)^{4})

24 x (3 x^{2} + 1)^{3}

Solution steps

\frac{d}{d x} ((3 x^{2} + 1)^{4})

Apply the chain rule:

4 (3 x^{2} + 1)^{3} \frac{d}{d x} (3 x^{2} + 1)

= 4 (3 x^{2} + 1)^{3} \frac{d}{d x} (3 x^{2} + 1)

\frac{d}{d x} (3 x^{2} + 1) = 6 x

= 4 (3 x^{2} + 1)^{3} \cdot 6 x

Simplify

= 24 x (3 x^{2} + 1)^{3}

k = 1 \sum \infty \frac{k ^{3}}{3 ^{k}}

y^{^{'}} + 3 y = 2 e^{- 3 x}

y = x^{3} - x, (- 1, 0)

f (x) = \frac{2}{x}, at x = - 1

\frac{1}{x} d y - \frac{y}{x ^{2}} d x = 0

What is the derivative of (3x^2+1^4) ?
The derivative of (3x^2+1^4) is 24x(3x^2+1)^3
What is the first derivative of (3x^2+1^4) ?
The first derivative of (3x^2+1^4) is 24x(3x^2+1)^3