What is the integral from 0 to 3pi of sin(x) ?

The integral from 0 to 3pi of sin(x) is 2

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integral from 0 to 3pi of sin(x)

\int_{0}^{3 π} sin (x) d x

2

Solution steps

\int_{0}^{3 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{3 π}

Compute the boundaries:

2

= 2

\frac{1}{5 + 7 x}

\int \frac{cos ^{2} ( x )}{4 + sin ( 2 x )} d x

\frac{d}{d x} (2 x^{3} - 9 x^{2} + 12 x)

\int_{1}^{2} \frac{x ^{2} + 1}{x} d x

t y^{^{'}} + t y = 1 - y

What is the integral from 0 to 3pi of sin(x) ?
The integral from 0 to 3pi of sin(x) is 2