What is the limit as x approaches 2 of [x^2f(x)] ?

The limit as x approaches 2 of [x^2f(x)] is 4f(2)

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limit as x approaches 2 of [x^2f(x)]

x \to 2 lim ([x^{2} f (x)])

4 f (2)

Solution steps

x \to 2 lim (x^{2} f (x))

Plug in the value

x = 2

, assuming the function is continuous at this point

= 2^{2} f (2)

Simplify

= 4 f (2)

f (x) = - 3 x^{2}, at x = 1

5 x^{3} - 3 x^{5}

(x y^{2}) \frac{d y}{d x} = y^{3} - x^{3}

\int x^{2} x - 2 d x

\int_{1}^{4} - 9 t ln (t) d t

What is the limit as x approaches 2 of [x^2f(x)] ?
The limit as x approaches 2 of [x^2f(x)] is 4f(2)