What is the solution for y(1+x^2)y^'-x(1+y^2)=0,y(0)=sqrt(3) ?

The solution for y(1+x^2)y^'-x(1+y^2)=0,y(0)=sqrt(3) is y=sqrt(4x^2+3)

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y(1+x^2)y^'-x(1+y^2)=0,y(0)=sqrt(3)

y (1 + x^{2}) y^{^{'}} - x (1 + y^{2}) = 0, y (0) = 3

y = 4 x^{2} + 3

Solution steps

y (1 + x^{2}) y^{'} (x) - x (1 + y^{2}) = 0

Solve separable ODE:

y = 4 x^{2} + 3

y = 4 x^{2} + 3

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\frac{d}{d x} (\frac{1}{x} - \frac{4}{x ^{2}})

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What is the solution for y(1+x^2)y^'-x(1+y^2)=0,y(0)=sqrt(3) ?
The solution for y(1+x^2)y^'-x(1+y^2)=0,y(0)=sqrt(3) is y=sqrt(4x^2+3)