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Popular >

y^'+(2y)/x =-4/x

Solution

y^{^{'}} + \frac{2 y}{x} = - \frac{4}{x}

Solution

y = \frac{c _{1}}{x ^{2}} - 2

Solution steps

y^{'} (x) + \frac{2 y}{x} = - \frac{4}{x}

Solve separable ODE:

y = \frac{c _{1}}{x ^{2}} - 2

y = \frac{c _{1}}{x ^{2}} - 2

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+(2y)/x =-4/x ?
The solution for y^'+(2y)/x =-4/x is y=(c_{1})/(x^2)-2