What is the derivative of y=sqrt(2x+4) ?

The derivative of y=sqrt(2x+4) is 1/(sqrt(2x+4))

What is the first derivative of y=sqrt(2x+4) ?

The first derivative of y=sqrt(2x+4) is 1/(sqrt(2x+4))

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derivative of

y = 2 x + 4

\frac{1}{2 x + 4}

Solution steps

\frac{d}{d x} (2 x + 4)

Apply the chain rule:

\frac{1}{2 2 x + 4} \frac{d}{d x} (2 x + 4)

= \frac{1}{2 2 x + 4} \frac{d}{d x} (2 x + 4)

\frac{d}{d x} (2 x + 4) = 2

= \frac{1}{2 2 x + 4} \cdot 2

Simplify

\frac{1}{2 2 x + 4} \cdot 2 : \frac{1}{2 x + 4}

= \frac{1}{2 x + 4}

7 x - 8 y x^{2} + 1 (\frac{d y}{d x}) = 0

\int 9 x + \frac{1}{9 x} d x

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\frac{d}{d x} (ln (e^{4 x}))

\frac{d}{d y} (y cos (x - y))

What is the derivative of y=sqrt(2x+4) ?
The derivative of y=sqrt(2x+4) is 1/(sqrt(2x+4))
What is the first derivative of y=sqrt(2x+4) ?
The first derivative of y=sqrt(2x+4) is 1/(sqrt(2x+4))