What is laplacetransform 3sin(2t+5) ?

The answer to laplacetransform 3sin(2t+5) is (3(sin(5)s+2cos(5)))/(s^2+4)

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laplacetransform 3sin(2t+5)

laplace transform

3 sin (2 t + 5)

\frac{3 ( sin ( 5 ) s + 2 cos ( 5 ) )}{s ^{2} + 4}

Solution steps

L {3 sin (2 t + 5)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {sin (2 t + 5)}

L {sin (2 t + 5)} : \frac{sin ( 5 ) s + 2 cos ( 5 )}{s ^{2} + 4}

= 3 \cdot \frac{sin ( 5 ) s + 2 cos ( 5 )}{s ^{2} + 4}

Refine

3 \frac{sin ( 5 ) s + 2 cos ( 5 )}{s ^{2} + 4} : \frac{3 ( sin ( 5 ) s + 2 cos ( 5 ) )}{s ^{2} + 4}

= \frac{3 ( sin ( 5 ) s + 2 cos ( 5 ) )}{s ^{2} + 4}

\frac{d}{d θ} (sec (θ))

\frac{y ^{^{'}} - ( x y )}{( 1 + x )} = x

f (x) = \frac{9 + 4 x - 8 x}{x}

2 y = 5 x, y = 5, 2 y + 4 x = 9

\int \frac{1}{z ^{3} z ^{2} - 25} d z

What is laplacetransform 3sin(2t+5) ?
The answer to laplacetransform 3sin(2t+5) is (3(sin(5)s+2cos(5)))/(s^2+4)