What is the derivative of asin(bx+c+d) ?

The derivative of asin(bx+c+d) is abcos(bx+c)

What is the first derivative of asin(bx+c+d) ?

The first derivative of asin(bx+c+d) is abcos(bx+c)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (a sin (b x + c) + d)

ab cos (b x + c)

Solution steps

\frac{d}{d x} (a sin (b x + c) + d)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a sin (b x + c)) + \frac{dd}{d x}

\frac{d}{d x} (a sin (b x + c)) = a cos (b x + c) b

\frac{dd}{d x} = 0

= a cos (b x + c) b + 0

Simplify

= ab cos (b x + c)

\int 5 e^{a x} d x

\int_{0}^{6} (6 - x) d x

\frac{d y}{d x}, (5 x - y)^{2} - 5 y = 2

\frac{\partial}{\partial x} (arccot (\frac{x}{y}))

\frac{d}{d x} (\frac{x + 6}{x - 6})

What is the derivative of asin(bx+c+d) ?
The derivative of asin(bx+c+d) is abcos(bx+c)
What is the first derivative of asin(bx+c+d) ?
The first derivative of asin(bx+c+d) is abcos(bx+c)