What is the derivative of \sqrt[5]{x^2}+4sqrt(x^7) ?

The derivative of \sqrt[5]{x^2}+4sqrt(x^7) is (2+70x^{31/10})/(5x^{3/5)}

What is the first derivative of \sqrt[5]{x^2}+4sqrt(x^7) ?

The first derivative of \sqrt[5]{x^2}+4sqrt(x^7) is (2+70x^{31/10})/(5x^{3/5)}

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\frac{d}{d x} (5 x^{2} + 4 x^{7})

\frac{2 + 70 x ^{\frac{31}{10}}}{5 x ^{\frac{3}{5}}}

Solution steps

\frac{d}{d x} (5 x^{2} + 4 x^{7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (4 x^{7})

\frac{d}{d x} (5 x^{2}) = \frac{2}{5 x ^{\frac{3}{5}}}

\frac{d}{d x} (4 x^{7}) = 14 x^{\frac{5}{2}}

= \frac{2}{5 x ^{\frac{3}{5}}} + 14 x^{\frac{5}{2}}

Simplify

\frac{2}{5 x ^{\frac{3}{5}}} + 14 x^{\frac{5}{2}} : \frac{2 + 70 x ^{\frac{31}{10}}}{5 x ^{\frac{3}{5}}}

= \frac{2 + 70 x ^{\frac{31}{10}}}{5 x ^{\frac{3}{5}}}

\frac{d}{d x} (\frac{2 ^{x}}{x} + x - lo g_{2} (x))

(- 19, - 6), (15, 16)

\int sin^{2} (4 x) cos (4 x) d x

\frac{\partial}{\partial y} (y cos (x))

x \to + 1 lim (ln (x) - 5 x)

What is the derivative of \sqrt[5]{x^2}+4sqrt(x^7) ?
The derivative of \sqrt[5]{x^2}+4sqrt(x^7) is (2+70x^{31/10})/(5x^{3/5)}
What is the first derivative of \sqrt[5]{x^2}+4sqrt(x^7) ?
The first derivative of \sqrt[5]{x^2}+4sqrt(x^7) is (2+70x^{31/10})/(5x^{3/5)}