What is the integral of 1/(2x+xln(x)) ?

The integral of 1/(2x+xln(x)) is ln|2+ln(x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(2x+xln(x))

\int \frac{1}{2 x + x ln ( x )} d x

ln ∣ 2 + ln (x) ∣ + C

Solution steps

\int \frac{1}{2 x + x ln ( x )} d x

Apply u-substitution

: \int \frac{1}{2 + u} d u

= \int \frac{1}{2 + u} d u

Apply u-substitution

: \int \frac{1}{v} d v

= \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= ln ∣ v ∣

Substitute back

= ln ∣ 2 + ln (x) ∣

Add a constant to the solution

= ln ∣ 2 + ln (x) ∣ + C

\frac{\partial}{\partial x} (\frac{7 y}{x ^{\frac{1}{2}}})

\frac{( e ^{- s} )}{s ^{2}}

\int (5 + 4 x^{2})^{2} d x

\int_{0}^{\frac{π}{2}} sin^{5} (2 x) d x

\int tan^{3} (x) sec (x) d x

What is the integral of 1/(2x+xln(x)) ?
The integral of 1/(2x+xln(x)) is ln|2+ln(x)|+C