What is the derivative of f(x)= 1/(x+6) ?

The derivative of f(x)= 1/(x+6) is -1/((x+6)^2)

What is the first derivative of f(x)= 1/(x+6) ?

The first derivative of f(x)= 1/(x+6) is -1/((x+6)^2)

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derivative of

f (x) = \frac{1}{x + 6}

- \frac{1}{( x + 6 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 6})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 6)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 6 ) ^{2}} \frac{d}{d x} (x + 6)

= - \frac{1}{( x + 6 ) ^{2}} \frac{d}{d x} (x + 6)

\frac{d}{d x} (x + 6) = 1

= - \frac{1}{( x + 6 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 6 ) ^{2}}

\frac{e ^{y} + e ^{- y}}{2}

\int e^{y^{2}} d y

\int \frac{10}{8 x - 4 x ^{2}} d x

\int_{\frac{1}{2}}^{\frac{e}{2}} ln (2 x) d x

\frac{( tan ( x ) - 1 )}{sec ( x )}

What is the derivative of f(x)= 1/(x+6) ?
The derivative of f(x)= 1/(x+6) is -1/((x+6)^2)
What is the first derivative of f(x)= 1/(x+6) ?
The first derivative of f(x)= 1/(x+6) is -1/((x+6)^2)