What is (\partial)/(\partial u)(asin(u)cos(v)) ?

The answer to (\partial)/(\partial u)(asin(u)cos(v)) is acos(v)cos(u)

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(\partial)/(\partial u)(asin(u)cos(v))

\frac{\partial}{\partial u} (a sin (u) cos (v))

a cos (v) cos (u)

Solution steps

\frac{\partial}{\partial u} (a sin (u) cos (v))

Treat

a, v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a cos (v) \frac{\partial}{\partial u} (sin (u))

Apply the common derivative:

\frac{\partial}{\partial u} (sin (u)) = cos (u)

= a cos (v) cos (u)

f (x) = \frac{216}{x ^{2} + 36}

\frac{d x}{d t} = \frac{4}{x e ^{t + 3 x}}

- \frac{2 ( z ^{2} + 1 )}{z ^{2}}

\frac{d}{d t} (a t^{5} - 5 b t^{3})

\frac{\partial}{\partial x} (5 x y^{3})

What is (\partial)/(\partial u)(asin(u)cos(v)) ?
The answer to (\partial)/(\partial u)(asin(u)cos(v)) is acos(v)cos(u)