What is laplacetransform 2cos(4t) ?

The answer to laplacetransform 2cos(4t) is (2s)/(s^2+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 2cos(4t)

laplace transform

2 cos (4 t)

\frac{2 s}{s ^{2} + 16}

Solution steps

L {2 cos (4 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {cos (4 t)}

L {cos (4 t)} : \frac{s}{s ^{2} + 16}

= 2 \cdot \frac{s}{s ^{2} + 16}

Refine

2 \frac{s}{s ^{2} + 16} : \frac{2 s}{s ^{2} + 16}

= \frac{2 s}{s ^{2} + 16}

\int \frac{x ^{2} - x + 20}{x ^{3} + 5 x} d x

x \to 4 lim (\frac{x - 4}{x - 4})

\int (e^{x} ln (e^{(2 x)})) d x

\int - 9 x \cdot e^{x} d x

n = 0 \sum \infty \frac{n}{( n ^{2} + 1 )}

What is laplacetransform 2cos(4t) ?
The answer to laplacetransform 2cos(4t) is (2s)/(s^2+16)