What is the derivative of 2x^{4pi} ?

The derivative of 2x^{4pi} is 8pix^{4pi-1}

What is the first derivative of 2x^{4pi} ?

The first derivative of 2x^{4pi} is 8pix^{4pi-1}

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\frac{d}{d x} (2 x^{4 π})

8 π x^{4 π - 1}

Solution steps

\frac{d}{d x} (2 x^{4 π})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{4 π})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 4 π x^{4 π - 1}

Simplify

= 8 π x^{4 π - 1}

\int \frac{x + 4}{x ^{3} + x ^{2} - 2} d x

\frac{d}{d y} (x^{y^{z}})

f (x) = \frac{5}{1 - 9 x}

f (x) = 6 e^{x} + 4 x^{2}

\frac{\partial}{\partial y} (cos (12 x) sin (3 y))

What is the derivative of 2x^{4pi} ?
The derivative of 2x^{4pi} is 8pix^{4pi-1}
What is the first derivative of 2x^{4pi} ?
The first derivative of 2x^{4pi} is 8pix^{4pi-1}