What is the integral of x(sqrt(x+1)) ?

The integral of x(sqrt(x+1)) is 2/5 (x+1)^{5/2}-2/3 (x+1)^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x(sqrt(x+1))

\int x (x + 1) d x

\frac{2}{5} (x + 1)^{\frac{5}{2}} - \frac{2}{3} (x + 1)^{\frac{3}{2}} + C

Solution steps

\int x x + 1 d x

Apply u-substitution

: \int (u - 1) u d u

= \int (u - 1) u d u

Expand

(u - 1) u : u^{\frac{3}{2}} - u

= \int u^{\frac{3}{2}} - u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{3}{2}} d u - \int u d u

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int u d u = \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{5} u^{\frac{5}{2}} - \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x + 1

= \frac{2}{5} (x + 1)^{\frac{5}{2}} - \frac{2}{3} (x + 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} (x + 1)^{\frac{5}{2}} - \frac{2}{3} (x + 1)^{\frac{3}{2}} + C

\int \frac{1 + x ^{2}}{x} d x

45 + 22 sin (\frac{2 π}{52} (t - 10))

\int_{0}^{3} e^{- x} d x

12 y^{^{''}} - 5 y^{^{'}} - 3 y = 0

12 t^{5}

What is the integral of x(sqrt(x+1)) ?
The integral of x(sqrt(x+1)) is 2/5 (x+1)^{5/2}-2/3 (x+1)^{3/2}+C