What is the solution for y^{''}+9y=cos(10t) ?

The solution for y^{''}+9y=cos(10t) is y=c_{1}cos(3t)+c_{2}sin(3t)-1/91 cos(10t)

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y^{''}+9y=cos(10t)

y^{^{''}} + 9 y = cos (10 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{1}{91} cos (10 t)

Solution steps

y^{''} (t) + 9 y = cos (10 t)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{1}{91} cos (10 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{1}{91} cos (10 t)

\frac{d}{d x} (\frac{sin ( x )}{x + tan ( x )})

\frac{\partial}{\partial x} (\frac{3}{t})

\int \frac{3}{x - 2} d x

y = e^{e^{4 x^{4}}}

x \to \frac{1}{3} lim (\frac{x + 4}{x + 5})

What is the solution for y^{''}+9y=cos(10t) ?
The solution for y^{''}+9y=cos(10t) is y=c_{1}cos(3t)+c_{2}sin(3t)-1/91 cos(10t)