What is the derivative of y=(x-2)/(x^2) ?

The derivative of y=(x-2)/(x^2) is (-x+4)/(x^3)

What is the first derivative of y=(x-2)/(x^2) ?

The first derivative of y=(x-2)/(x^2) is (-x+4)/(x^3)

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derivative of

y = \frac{x - 2}{x ^{2}}

\frac{- x + 4}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x - 2}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 2 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( x - 2 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (x - 2) = 1

\frac{d}{d x} (x^{2}) = 2 x

= \frac{1 \cdot x ^{2} - 2 x ( x - 2 )}{( x ^{2} ) ^{2}}

Simplify

\frac{1 \cdot x ^{2} - 2 x ( x - 2 )}{( x ^{2} ) ^{2}} : \frac{- x + 4}{x ^{3}}

= \frac{- x + 4}{x ^{3}}

f (x) = (x^{2} + 3)^{6}

x \to 3 lim (x^{2} - 1)

\int x (5 + 2 x)^{4} d x

\int (sec (2 x))^{2} d x

2 tan (x)

What is the derivative of y=(x-2)/(x^2) ?
The derivative of y=(x-2)/(x^2) is (-x+4)/(x^3)
What is the first derivative of y=(x-2)/(x^2) ?
The first derivative of y=(x-2)/(x^2) is (-x+4)/(x^3)