What is the solution for (dy)/(dx)=y^2e^{3x},y(0)=4 ?

The solution for (dy)/(dx)=y^2e^{3x},y(0)=4 is y=-(12)/(4e^{3x)-7}

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(dy)/(dx)=y^2e^{3x},y(0)=4

\frac{d y}{d x} = y^{2} e^{3 x}, y (0) = 4

y = - \frac{12}{4 e ^{3 x} - 7}

Solution steps

\frac{d y}{d x} = y^{2} e^{3 x}

Solve separable ODE:

y = - \frac{12}{4 e ^{3 x} - 7}

y = - \frac{12}{4 e ^{3 x} - 7}

x \to 4 lim (- x + 7)

\frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} - 6 y = 36 x

y = 1 + t - 1 - t

n = 1 \sum \infty \frac{2}{1 0 ^{n}}

\int (\frac{x + 6}{x}) d x

What is the solution for (dy)/(dx)=y^2e^{3x},y(0)=4 ?
The solution for (dy)/(dx)=y^2e^{3x},y(0)=4 is y=-(12)/(4e^{3x)-7}