What is (\partial)/(\partial y)(2e^{-ln(y)}y) ?

The answer to (\partial)/(\partial y)(2e^{-ln(y)}y) is 0

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(\partial)/(\partial y)(2e^{-ln(y)}y)

\frac{\partial}{\partial y} (2 e^{- l n (y)} y)

0

Solution steps

\frac{\partial}{\partial y} (2 e^{- l n (y)} y)

2 e^{- l n (y)} y = 2

= \frac{\partial}{\partial y} (2)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d ^{2}}{d x ^{2}} (cos (- 1.5 x))

\int 25 - t^{2} d t

\int x^{8} e^{- x^{9}} d x

f (x) = 5 sec (x), at x = \frac{π}{6}

\frac{d}{d x} ((3 x^{6} + 8 x^{3})^{4})

What is (\partial)/(\partial y)(2e^{-ln(y)}y) ?
The answer to (\partial)/(\partial y)(2e^{-ln(y)}y) is 0