What is the integral from-2 to 2 of (3x^3-10) ?

The integral from-2 to 2 of (3x^3-10) is -40

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integral from-2 to 2 of (3x^3-10)

\int_{- 2}^{2} (3 x^{3} - 10) d x

- 40

Solution steps

\int_{- 2}^{2} 3 x^{3} - 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 3 x^{3} d x - \int_{- 2}^{2} 10 d x

\int_{- 2}^{2} 3 x^{3} d x = 0

\int_{- 2}^{2} 10 d x = 40

= 0 - 40

Simplify

= - 40

y^{^{'}} = (x + y - 4)

\int x cos (n \cdot \frac{π}{3} \cdot x) d x

x \to - \infty lim (x \cdot (x))

y = x^{2}, x = 3, x = - 3

f (x) = - x^{2} + 5

What is the integral from-2 to 2 of (3x^3-10) ?
The integral from-2 to 2 of (3x^3-10) is -40