What is the d/(dt)(sin^3(t)) ?

The d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)

What is the first d/(dt)(sin^3(t)) ?

The first d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)

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\frac{d}{d t} (sin^{3} (t))

3 sin^{2} (t) cos (t)

Solution steps

\frac{d}{d t} (sin^{3} (t))

Apply the chain rule:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 3 (sin (t))^{2} cos (t)

Simplify

= 3 sin^{2} (t) cos (t)

x (\frac{d y}{d x}) + (3 x + 1) y = e^{- 3 x}

\int_{0}^{4} 3 d x

\frac{d}{d x} (x^{2} tan (2 x^{5}))

\int_{11}^{12} 14 arccot (x) d x

\int_{1}^{e} ln (ll x) d x

What is the d/(dt)(sin^3(t)) ?
The d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)
What is the first d/(dt)(sin^3(t)) ?
The first d/(dt)(sin^3(t)) is 3sin^2(t)cos(t)