What is taylor 2/(1-x),0 ?

The answer to taylor 2/(1-x),0 is 2+2x+2x^2+2x^3+2x^4+\ldots

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taylor 2/(1-x),0

taylor

\frac{2}{1 - x}, 0

2 + 2 x + 2 x^{2} + 2 x^{3} + 2 x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 2 + \frac{\frac{d}{d x} ( \frac{2}{1 - x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{2}{1 - x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{2}{1 - x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 2 + \frac{2}{1 !} x + \frac{4}{2 !} x^{2} + \frac{12}{3 !} x^{3} + \frac{48}{4 !} x^{4} + \dots

Refine

= 2 + 2 x + 2 x^{2} + 2 x^{3} + 2 x^{4} + \dots

\frac{1}{1 + x ^{2}}, 0

\int_{0}^{1} x^{2} (2 x^{3} - 1)^{4} d x

\frac{d}{d x} (9 e^{2 x})

\frac{\partial}{\partial x} (x^{2} y^{0.5})

\int \frac{e ^{6 s i n (x)}}{sec ( x )} d x

What is taylor 2/(1-x),0 ?
The answer to taylor 2/(1-x),0 is 2+2x+2x^2+2x^3+2x^4+\ldots