What is the derivative of (x^3-2^2) ?

The derivative of (x^3-2^2) is 6x^2(x^3-2)

What is the first derivative of (x^3-2^2) ?

The first derivative of (x^3-2^2) is 6x^2(x^3-2)

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\frac{d}{d x} ((x^{3} - 2)^{2})

6 x^{2} (x^{3} - 2)

Solution steps

\frac{d}{d x} ((x^{3} - 2)^{2})

Apply the chain rule:

2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

= 2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

\frac{d}{d x} (x^{3} - 2) = 3 x^{2}

= 2 (x^{3} - 2) \cdot 3 x^{2}

Simplify

= 6 x^{2} (x^{3} - 2)

\int 1000 t e^{- 0.5 t} d t

y^{^{''}} - 4 y^{^{'}} + 4 y = 120 x^{2} e^{2 x}

x \to - 4 lim (\frac{x ^{2} + 5}{x + 4})

3 x^{2} y^{^{'}} = y^{^{'}} + 3 x e^{- y}

\frac{d}{d z} (- z)

What is the derivative of (x^3-2^2) ?
The derivative of (x^3-2^2) is 6x^2(x^3-2)
What is the first derivative of (x^3-2^2) ?
The first derivative of (x^3-2^2) is 6x^2(x^3-2)