What is the tangent of f(x)=2x^2-2x-4,\at x=1 ?

The tangent of f(x)=2x^2-2x-4,\at x=1 is y=2x-6

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tangent of f(x)=2x^2-2x-4,\at x=1

tangent of

f (x) = 2 x^{2} - 2 x - 4, at x = 1

y = 2 x - 6

Solution steps

Find the tangent point:

(1, - 4)

Find the slope of

f (x) = 2 x^{2} - 2 x - 4 : \frac{df ( x )}{d x} = 4 x - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(1, - 4) : y = 2 x - 6

y = 2 x - 6

y = (ln (4) x^{2}) (- x^{3} - 4)

y = x + 12, y = x^{2}

\int \frac{1}{x ^{2} 121 - x ^{2}} d x

x^{2} - 1, - x^{2}

t \to 0 lim (cos (2 t))

What is the tangent of f(x)=2x^2-2x-4,\at x=1 ?
The tangent of f(x)=2x^2-2x-4,\at x=1 is y=2x-6