What is laplacetransform te^{2t} ?

The answer to laplacetransform te^{2t} is 1/((s-2)^2)

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laplacetransform te^{2t}

laplace transform

t e^{2 t}

\frac{1}{( s - 2 ) ^{2}}

Solution steps

L {e^{2 t} t}

Use Laplace Transform table:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

For

t e^{2 t} : f (t) = e^{2 t}, k = 1

= (- 1)^{1} \frac{d}{d s} (L {e^{2 t}})

L {e^{2 t}} : \frac{1}{s - 2}

\frac{d}{d s} (\frac{1}{s - 2}) = - \frac{1}{( s - 2 ) ^{2}}

= (- 1)^{1} (- \frac{1}{( s - 2 ) ^{2}})

= \frac{1}{( s - 2 ) ^{2}}

sin^{2} (p i x)

\int \frac{6 x ^{3} + 7 x}{( x ^{2} + 2 ) ^{2}} d x

\frac{2}{( s + 1 ) ^{3}}

\frac{d}{d x} (- 4 e^{- 2.5 x})

\int sin^{7} (x) d x

What is laplacetransform te^{2t} ?
The answer to laplacetransform te^{2t} is 1/((s-2)^2)