What is the derivative of y=arctan(x-2) ?

The derivative of y=arctan(x-2) is 1/(x^2-4x+5)

What is the first derivative of y=arctan(x-2) ?

The first derivative of y=arctan(x-2) is 1/(x^2-4x+5)

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derivative of

y = arctan (x - 2)

\frac{1}{x ^{2} - 4 x + 5}

Solution steps

\frac{d}{d x} (arctan (x - 2))

Apply the chain rule:

\frac{1}{( x - 2 ) ^{2} + 1} \frac{d}{d x} (x - 2)

= \frac{1}{( x - 2 ) ^{2} + 1} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= \frac{1}{( x - 2 ) ^{2} + 1} \cdot 1

Simplify

\frac{1}{( x - 2 ) ^{2} + 1} \cdot 1 : \frac{1}{x ^{2} - 4 x + 5}

= \frac{1}{x ^{2} - 4 x + 5}

\int (a^{\frac{2}{3}} - x^{\frac{2}{3}})^{3} d x

\frac{1}{x - 1}, 9

\int \frac{tan ( x )}{cos ^{2} ( x )} d x

x \to \frac{π}{2} lim (7 sin (x))

\int \frac{1}{x ^{- 1} + x ^{- 3}} d x

What is the derivative of y=arctan(x-2) ?
The derivative of y=arctan(x-2) is 1/(x^2-4x+5)
What is the first derivative of y=arctan(x-2) ?
The first derivative of y=arctan(x-2) is 1/(x^2-4x+5)