What is the derivative of f(x)=2x^2+3x-2 ?

The derivative of f(x)=2x^2+3x-2 is 4x+3

What is the first derivative of f(x)=2x^2+3x-2 ?

The first derivative of f(x)=2x^2+3x-2 is 4x+3

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derivative of

f (x) = 2 x^{2} + 3 x - 2

4 x + 3

Solution steps

\frac{d}{d x} (2 x^{2} + 3 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 4 x + 3 - 0

Simplify

= 4 x + 3

y = 3 x^{2} + 2 x + 9

\int \frac{1}{y - 2} d y

\frac{\partial}{\partial y} (8 x y^{2} + x^{2})

n = 1 \sum \infty (- 1)^{n} n

n \to \infty lim ((n!)^{2})

What is the derivative of f(x)=2x^2+3x-2 ?
The derivative of f(x)=2x^2+3x-2 is 4x+3
What is the first derivative of f(x)=2x^2+3x-2 ?
The first derivative of f(x)=2x^2+3x-2 is 4x+3