What is the derivative of-3cos(x+4sin(x)) ?

The derivative of-3cos(x+4sin(x)) is 3sin(x)+4cos(x)

What is the first derivative of-3cos(x+4sin(x)) ?

The first derivative of-3cos(x+4sin(x)) is 3sin(x)+4cos(x)

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\frac{d}{d x} (- 3 cos (x) + 4 sin (x))

3 sin (x) + 4 cos (x)

Solution steps

\frac{d}{d x} (- 3 cos (x) + 4 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 cos (x)) + \frac{d}{d x} (4 sin (x))

\frac{d}{d x} (3 cos (x)) = - 3 sin (x)

\frac{d}{d x} (4 sin (x)) = 4 cos (x)

= - (- 3 sin (x)) + 4 cos (x)

Simplify

= 3 sin (x) + 4 cos (x)

y^{^{'}} - \frac{y}{x} = - x e^{- x}

f (x) = ln (\frac{3}{2}) x^{8}

\frac{d y}{d x} = 8 x y cos (x^{2})

\int 3 x^{5} d x

\int \frac{1 + x}{1 + 9 x ^{2}} d x

What is the derivative of-3cos(x+4sin(x)) ?
The derivative of-3cos(x+4sin(x)) is 3sin(x)+4cos(x)
What is the first derivative of-3cos(x+4sin(x)) ?
The first derivative of-3cos(x+4sin(x)) is 3sin(x)+4cos(x)