What is the limit as x approaches+0 of (tan(6x))/(sin(4x)) ?

The limit as x approaches+0 of (tan(6x))/(sin(4x)) is 3/2

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limit as x approaches+0 of (tan(6x))/(sin(4x))

x \to + 0 lim (\frac{tan ( 6 x )}{sin ( 4 x )})

\frac{3}{2}

Decimal

1.5

Solution steps

x \to 0 lim (\frac{tan ( 6 x )}{sin ( 4 x )})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{tan ( 6 x )}{sin ( 4 x )}) = \frac{3}{2}

x \to 0 + lim (\frac{tan ( 6 x )}{sin ( 4 x )}) = \frac{3}{2}

= \frac{3}{2}

\int (x^{2} + 1) 5^{x^{3} + 3 x} d x

(4 + 3 x)^{^{'}}

\frac{d}{d x} (\frac{1 + 2 x ^{2}}{( 1 - 2 x ^{2} ) ^{2}})

\int x^{4} \cdot e^{- x^{5}} d x

x \to 0 lim (\frac{cos ( a x ) - cos ( b x )}{x ^{2}})

What is the limit as x approaches+0 of (tan(6x))/(sin(4x)) ?
The limit as x approaches+0 of (tan(6x))/(sin(4x)) is 3/2