What is the solution for y^'=1-sin(y),y(0)=0 ?

The solution for y^'=1-sin(y),y(0)=0 is y=2arctan(t/(t+2))+2pin

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y^'=1-sin(y),y(0)=0

y^{^{'}} = 1 - sin (y), y (0) = 0

y = 2 arctan (\frac{t}{t + 2}) + 2 πn

Solution steps

y^{'} (t) = 1 - sin (y)

Solve separable ODE:

y = 2 arctan (\frac{t}{t + 2}) + 2 πn

y = 2 arctan (\frac{t}{t + 2}) + 2 πn

\int_{- 1}^{1} 3 x^{2} (2 x^{3} + 1)^{2} d x

\int x^{3} - 3 x^{2} d x

x \to 2 + lim (\frac{2}{( x - 2 ) ^{5}})

\int 5 x e^{10 x} d x

x \to 0 + lim (\frac{x ^{2} - 3 x + 2}{x ^{3} - 2 x ^{2}})

What is the solution for y^'=1-sin(y),y(0)=0 ?
The solution for y^'=1-sin(y),y(0)=0 is y=2arctan(t/(t+2))+2pin