What is the derivative of sqrt(8x-1) ?

The derivative of sqrt(8x-1) is 4/(sqrt(8x-1))

What is the first derivative of sqrt(8x-1) ?

The first derivative of sqrt(8x-1) is 4/(sqrt(8x-1))

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\frac{d}{d x} (8 x - 1)

\frac{4}{8 x - 1}

Solution steps

\frac{d}{d x} (8 x - 1)

Apply the chain rule:

\frac{1}{2 8 x - 1} \frac{d}{d x} (8 x - 1)

= \frac{1}{2 8 x - 1} \frac{d}{d x} (8 x - 1)

\frac{d}{d x} (8 x - 1) = 8

= \frac{1}{2 8 x - 1} \cdot 8

Simplify

\frac{1}{2 8 x - 1} \cdot 8 : \frac{4}{8 x - 1}

= \frac{4}{8 x - 1}

10 x y y^{^{'}} = 1 - y^{2}

x \to \infty lim (\frac{x ^{3} + 9 x}{6 x ^{3} - x ^{2} + 3})

\frac{d}{d x} (6 x - 1)

\int_{- 2}^{2} x^{4} - 8 x^{2} + 16 d x

n = 0 \sum \infty \frac{2 n}{1 + n ^{4}}

What is the derivative of sqrt(8x-1) ?
The derivative of sqrt(8x-1) is 4/(sqrt(8x-1))
What is the first derivative of sqrt(8x-1) ?
The first derivative of sqrt(8x-1) is 4/(sqrt(8x-1))