What is the derivative of f(x)=sqrt(3+4x) ?

The derivative of f(x)=sqrt(3+4x) is 2/(sqrt(3+4x))

What is the first derivative of f(x)=sqrt(3+4x) ?

The first derivative of f(x)=sqrt(3+4x) is 2/(sqrt(3+4x))

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derivative of

f (x) = 3 + 4 x

\frac{2}{3 + 4 x}

Solution steps

\frac{d}{d x} (3 + 4 x)

Apply the chain rule:

\frac{1}{2 3 + 4 x} \frac{d}{d x} (3 + 4 x)

= \frac{1}{2 3 + 4 x} \frac{d}{d x} (3 + 4 x)

\frac{d}{d x} (3 + 4 x) = 4

= \frac{1}{2 3 + 4 x} \cdot 4

Simplify

\frac{1}{2 3 + 4 x} \cdot 4 : \frac{2}{3 + 4 x}

= \frac{2}{3 + 4 x}

(x + 2 y) y^{^{'}} = - y - 2 x

\frac{( 5 + 5 s )}{( s ^{2} + 25 )}

\frac{s ^{2}}{s ^{2} + 4 s + 5}

4 - x^{2}, 14 - 7 x

x^{3} - 3 x^{2} + 3 x - 3

What is the derivative of f(x)=sqrt(3+4x) ?
The derivative of f(x)=sqrt(3+4x) is 2/(sqrt(3+4x))
What is the first derivative of f(x)=sqrt(3+4x) ?
The first derivative of f(x)=sqrt(3+4x) is 2/(sqrt(3+4x))