What is the derivative of f(x)= 2/(1-8x) ?

The derivative of f(x)= 2/(1-8x) is (16)/((1-8x)^2)

What is the first derivative of f(x)= 2/(1-8x) ?

The first derivative of f(x)= 2/(1-8x) is (16)/((1-8x)^2)

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derivative of

f (x) = \frac{2}{1 - 8 x}

\frac{16}{( 1 - 8 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{1 - 8 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{1 - 8 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((1 - 8 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 8 x ) ^{2}} \frac{d}{d x} (1 - 8 x)

= - \frac{1}{( 1 - 8 x ) ^{2}} \frac{d}{d x} (1 - 8 x)

\frac{d}{d x} (1 - 8 x) = - 8

= 2 (- \frac{1}{( 1 - 8 x ) ^{2}} (- 8))

Simplify

2 (- \frac{1}{( 1 - 8 x ) ^{2}} (- 8)) : \frac{16}{( 1 - 8 x ) ^{2}}

= \frac{16}{( 1 - 8 x ) ^{2}}

\int \frac{y ^{2}}{2} d y

\frac{\partial}{\partial x} (\frac{1}{2} x^{2})

x \to 0 + lim (2 sin (x) ln (x))

y = x ln (x)

θ \to - \frac{π}{2} - lim (sec (θ))

What is the derivative of f(x)= 2/(1-8x) ?
The derivative of f(x)= 2/(1-8x) is (16)/((1-8x)^2)
What is the first derivative of f(x)= 2/(1-8x) ?
The first derivative of f(x)= 2/(1-8x) is (16)/((1-8x)^2)