What is the derivative of 2x^2+x+1 ?

The derivative of 2x^2+x+1 is 4x+1

What is the first derivative of 2x^2+x+1 ?

The first derivative of 2x^2+x+1 is 4x+1

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derivative of

2 x^{2} + x + 1

4 x + 1

Solution steps

\frac{d}{d x} (2 x^{2} + x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 4 x + 1 + 0

Simplify

= 4 x + 1

f (x) = 5 - 4 x^{2}

\frac{d}{d x} (2 x - \frac{2}{x})

\frac{d y}{d t} = - 0.0077 y

f (x) = tan (x + 1)

y^{^{'}} = 0.1 - \frac{y}{400}

What is the derivative of 2x^2+x+1 ?
The derivative of 2x^2+x+1 is 4x+1
What is the first derivative of 2x^2+x+1 ?
The first derivative of 2x^2+x+1 is 4x+1